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Number Systems, Operations and Codes

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Important Questions

Important Questions

Number Systems, Operations and Codes

Asked in 2081.2Short Question2.5+2.5 Marks
1.
Perform the following conversion: (a) (0.625)10(0.625)_{10} to binary. (b) (173)8(173)_8 to decimal. [2.5+2.5]
Asked in 2081.2Short Question5 Marks
2.
Perform A−BA - B with the given binary numbers using 1’s complement. A=1010100A = 1010100, B=1000100B = 1000100. [5]
Asked in 2081Short Question5 Marks
3.
Perform following arithmetic operation:
a)101101+011011a) 101101 + 011011
b)101111−010101b) 101111 - 010101
[5]
Asked in 2081Short Question5 Marks
4.
Convert (257)₈ into hexadecimal and decimal number system. [5]
Asked in 2080Short Question5 Marks
5.
Convert (591.62)10(591.62)_{10} into hexadecimal and octal number system. [5]
Asked in 2079Short Question5 Marks
6.
Subtract (739.57)10(739.57)_{10} - (78.35)2(78.35)_2 using both 10's and 9's complement. [5]
Asked in 2079Short Question5 Marks
7.
Convert (110.101)8(110.101)_8 into binary and decimal number system. [5]
Asked in 2078Short Question5 Marks
8.
Subtract (111000.110)2(111000.110)_2 - (110100.101)2(110100.101)_2 using both 2's and 1's complement. [5]
Asked in 2078Short Question5 Marks
9.
Convert 51966.57 decimal number system into octal number system and hexadecimal number system. [5]
Asked in 2078Short Question5 Marks
10.
Convert (1011.110) into decimal. and hexadecimal [5]
Asked in 2077Short Question5 Marks
11.
Substract (1011.11- 1010.10) using 2's and l's complement. [5]
Asked in 2077Short Question5 Marks
12.
Convert (1011.110) into decimal and hexadecimal. [5]
ModelShort Question5 Marks
13.
a) Obtain the 9's and 10's complement of i) 13579 ii) 90090 decimal number. b) Convert 6524275 octal to hexadecimal [5]
ModelLong Question10 Marks
14.
The term LOGIC GATES is to be transmitted as 12 bytes of data. Each character in the term has an ASCII value. The system uses odd parity and left most bit is used as parity bit. An additional parity byte is also sent after the term. The following bytes have arrived at their destination. a. One of the bytes has an error after transmission. Locate which character contains an error. b. Locate the bit that has been transmitted incorrectly. c. Explain how you have arrived at your conclusion.
letters123456781L010011002O010011113G110001114I010010015C010000116⟨space⟩001000007G110001118A110001019T0101010010E0100010111S1101001112Parity byte11010010\begin{array}{|c|c|c|c|c|c|c|c|c|c|}\hline & \text{letters} & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline 1 & L & 0 & 1 & 0 & 0 & 1 & 1 & 0 & 0 \\ 2 & O & 0 & 1 & 0 & 0 & 1 & 1 & 1 & 1 \\ 3 & G & 1 & 1 & 0 & 0 & 0 & 1 & 1 & 1 \\ 4 & I & 0 & 1 & 0 & 0 & 1 & 0 & 0 & 1 \\ 5 & C & 0 & 1 & 0 & 0 & 0 & 0 & 1 & 1 \\ 6 & \langle \text{space} \rangle & 0 & 0 & 1 & 0 & 0 & 0 & 0 & 0 \\ 7 & G & 1 & 1 & 0 & 0 & 0 & 1 & 1 & 1 \\ 8 & A & 1 & 1 & 0 & 0 & 0 & \mathbf{1} & 0 & 1 \\ 9 & T & 0 & 1 & 0 & 1 & 0 & 1 & 0 & 0 \\ 10 & E & 0 & 1 & 0 & 0 & 0 & 1 & 0 & 1 \\ 11 & S & 1 & 1 & 0 & 1 & 0 & 0 & 1 & 1 \\ 12 & \text{Parity byte} & 1 & 1 & 0 & 1 & 0 & 0 & 1 & 0 \\ \hline \end{array}
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